(1/64)^x+2=8^2x

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Solution for (1/64)^x+2=8^2x equation: 



(1/64)^x+2=8^2x

We move all terms to the left:

(1/64)^x+2-(8^2x)=0



Domain of the equation: 64)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/64)^x-8^2x+2=0

We multiply all the terms by the denominator


(+1-8^2x*64)^x+2*64)^x=0

Wy multiply elements

(+1-8^2x*64)^x+128x=0

We add all the numbers together, and all the variables

128x+(+1-8^2x*64)^x=0

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